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A rectangle has a perimeter of 50 units. Its length and width are both whole numbers. What are the possible dimensions of the rectangle?
Solution:
The formula for the perimeter of a rectangle is:
P = 2L + 2W
2L + 2W = 50 \implies L + W = 25
(L, W) = (13, 12) \text{ or } (12, 13).
Answers:
The rectangle can have dimensions:
13x12
12x13